Hello list,
A coworker and I have been trying to use the first example in http://download.osgeo.org/grass/grass6_progman/pythonlib.html. We discovered that “import grass.script as grass” has to be changed to “import grass”. Below is the example and the error we are getting is this:
C:>m.test.py
Traceback (most recent call last):
File “C:\OSGeo4W\apps\grass\GRASS-~1.0SV/scripts\m.test.py”, line 31, in
options, flags = grass.parser()
File “C:\OSGeo4W\apps\grass\GRASS-~1.0SV\etc\python\grass.py”, line 208, in parser
os.execvp(“g.parser”, [name] + argv)
File “C:\OSGeo4W\apps\Python25\lib\os.py”, line 353, in execvp
_execvpe(file, args)
File “C:\OSGeo4W\apps\Python25\lib\os.py”, line 389, in _execvpe
func(fullname, *argrest)
OSError: [Errno 22] Invalid argument
Any ideas what is going on?
Bob
#====================================================
#!/usr/bin/env python
#%Module
#% description: Checks if vector map is 3D
#% keywords: vector
#%End
#%option
#% key: map
#% type: string
#% gisprompt: old,vector,vector
#% key_desc: name
#% description: Name of vector map
#% required: yes
#%end
import sys
import grass
def main():
info = grass.parse_command(‘v.info’,
flags = ‘t’,
map = options[‘map’])
if info[‘map3d’] == ‘1’:
print ‘Vector map is 3D’
else:
print ‘Vector map is 2D’
return 0
if name == “main”:
options, flags = grass.parser()
sys.exit(main())
Bob Moskovitz
Research Analyst I
Seismic Hazard Zonation Project
California Geological Survey
http://www.conservation.ca.gov/cgs/shzp
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